ICSE Class 10 Mathematics � Chapter 11
Central Angle: Angle at the center of the circle.
Inscribed Angle: Angle at any point on the circle (vertex on circumference).
Central Angle = 2 � Inscribed Angle
(if both subtend the same arc)
Theorem: Angles in the same segment of a circle are equal.
All inscribed angles subtending the same arc are equal.
Theorem: An angle inscribed in a semicircle is a right angle (90�).
If AB is a diameter and C is any point on the circle, then ?ACB = 90�
Cyclic Quadrilateral: A quadrilateral whose all four vertices lie on a circle.
Property 1: Opposite angles of a cyclic quadrilateral are supplementary.
?A + ?C = 180� and ?B + ?D = 180�
Property 2: Exterior angle of cyclic quadrilateral = Interior opposite angle.
Tangent: A line that touches the circle at exactly one point (point of tangency).
Theorem 1: The tangent at any point of a circle is perpendicular to the radius at that point.
If PT is tangent at T, then OT ? PT (?OTP = 90�)
Theorem 2: Tangents drawn from an external point to a circle are equal in length.
If PA and PB are tangents from P, then PA = PB
Additional Properties (Two Tangents from External Point):
Theorem: If two chords intersect inside a circle, then:
PA � PB = PC � PD
(Product of segments of one chord = Product of segments of other chord)
Theorem: If a tangent and a secant are drawn from an external point:
(Tangent)� = External segment � Whole secant
PT� = PA � PB
Theorem: The angle between a tangent and a chord at the point of contact equals the inscribed angle in the alternate segment.
?PTB = ?BAT (angle in alternate segment)
Example 1: In a circle, inscribed angle is 35�. Find the central angle subtending the same arc.
Central angle = 2 � Inscribed angle = 2 � 35� = 70�
Example 2: In cyclic quadrilateral ABCD, ?A = 70� and ?B = 115�. Find ?C and ?D.
?C = 180� - ?A = 180� - 70� = 110�
?D = 180� - ?B = 180� - 115� = 65�
Example 3: Two chords AB and CD intersect at P. If AP = 4, PB = 6, CP = 3, find PD.
AP � PB = CP � PD
4 � 6 = 3 � PD
PD = 8 cm
| Theorem | Statement |
|---|---|
| Central = 2 � Inscribed | ?at center = 2 � ?at circumference |
| Same Segment | Angles in same segment are equal |
| Semicircle | Angle in semicircle = 90� |
| Cyclic Quadrilateral | Opposite angles add to 180� |
| Tangent ? Radius | Tangent perpendicular to radius |
| Equal Tangents | Tangents from external point are equal |
| Intersecting Chords | PA � PB = PC � PD |
| Tangent-Secant | PT� = PA � PB |
BOARD In the figure, O is center of circle. ?AOB = 100�. Find ?ACB and ?ADB if C and D are points on the major and minor arcs respectively.
BOARD PA and PB are tangents to a circle with center O. If ?APB = 80�, find: (i) ?AOB (ii) ?OAB