Part I: Fill in the Blanks
Part II: Multiple Choice Questions (MCQs)
Solution: (b) $[ML^2T^{-3}A^{-1}]$
Solution: (b) $10\text{ J}$ (Since $W = qV = 2 \times 5 = 10$)
Solution: (a) Higher to lower potential
Solution: (a) $1.6 \times 10^{-19}\text{ J}$
Part III: Match the Following
Solution:
(P) Electrostatic Potential $\rightarrow$ (3) Volt
(Q) Work Done $\rightarrow$ (4) Joules
(R) Charge $\rightarrow$ (1) Coulomb
(S) Potential Difference $\rightarrow$ (2) $W/q$
Part I: Fill in the Blanks
Solution: $\frac{1}{4\pi\epsilon_0}\frac{q}{r}$
Solution: $2$ (Since $V \propto 1/r^2$)
Solution: $9 \times 10^9$
Solution: Equal (or Constant)
Part II: Multiple Choice Questions (MCQs)
Solution: (b) Half (Since $V \propto 1/r$)
Part III: True or False
Solution: False (It varies inversely with distance $r$, not $r^2$)
Part IV: Match the Following
Solution:
(P) Point Charge $\rightarrow$ (3) $\frac{kq}{r}$
(Q) Dipole (Axial) $\rightarrow$ (4) $\frac{kp}{r^2}$
(R) Dipole (Equatorial) $\rightarrow$ (1) $0$
(S) Inside Hollow Sphere $\rightarrow$ (2) Constant
Part I: Fill in the Blanks
Solution: Perpendicular ($90^\circ$)
Part II: Multiple Choice Questions (MCQs)
Solution: (c) Concentric spheres
Solution: (a) Parallel planes
Solution: (b) No (It would mean two different potentials at one point)
Solution: (a) $5\text{ V/m}$ ($E = |-\frac{dV}{dx}|$)
Part III: True or False
Solution: True (Electric field is the negative potential gradient)
Part I: Fill in the Blanks
Solution: $\frac{1}{4\pi\epsilon_0}\frac{q_1 q_2}{r}$
Solution: $-pE\cos\theta$ or $-\vec{p}\cdot\vec{E}$
Solution: $pE(\cos\theta_1 - \cos\theta_2)$
Part II: Multiple Choice Questions (MCQs)
Solution: (a) Increases (Work is done against repulsion)
Solution: (c) Parallel to E ($\theta = 0^\circ$)
Part III: Match the Following
Solution:
(P) $\theta = 0^\circ$ (Stable) $\rightarrow$ (2) $-pE$
(Q) $\theta = 90^\circ$ $\rightarrow$ (3) $0$
(R) $\theta = 180^\circ$ (Unstable) $\rightarrow$ (1) $+pE$
Part I: Fill in the Blanks
Solution: $4\pi\epsilon_0 R$
Solution: $\frac{\epsilon_0 A}{d}$
Solution: Increases (by factor $K$)
Solution: Potential Difference ($V$)
Part II: Multiple Choice Questions (MCQs)
Solution: (a) $C_1 + C_2$
Solution: (b) $2\mu\text{F}$ ($\frac{1}{C_s} = \frac{1}{4} + \frac{1}{4}$)
Solution: (d) All of these
Solution: (b) Doubles ($C \propto 1/d$)
Part III: Match the Following
Solution:
(P) Energy Density ($u$) $\rightarrow$ (2) $\frac{1}{2}\epsilon_0 E^2$
(Q) Energy Stored ($U$) $\rightarrow$ (1) $\frac{1}{2}CV^2$
(R) Series Equivalent ($C_s$) $\rightarrow$ (4) $(\frac{1}{C_1} + \frac{1}{C_2})^{-1}$
(S) Parallel Equivalent ($C_p$) $\rightarrow$ (3) $C_1 + C_2$