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Answer Key: Level 2 (Human Eye)

Class: 10 Science Topic: Concept Modules Solutions Max. Questions: 50
Module 1: Diagrammatic Analysis
1. (a) Iris (b) Retina (c) Ciliary Muscles. [Diagram: Human Eye with these parts labeled].
2. Myopia: Image forms in front of retina. Correction: Concave lens diverges rays to focus on retina.
[Diagram: Myopic Eye and Correction with Concave Lens]
3. Hypermetropia: Image forms behind retina. Correction: Convex lens converges rays to focus on retina.
[Diagram: Hypermetropic Eye and Correction with Convex Lens]
4. Dispersion by Prism. Top: Red (Least deviated). Bottom: Violet (Most deviated).
[Diagram: Dispersion showing VIBGYOR]
5. Two identical prisms placed inverted (Action and Opposition). First disperses white light, second recombines it.
[Diagram: Newton's Recombination Experiment]
6. Sunlight enters water droplet $\to$ Refraction & Dispersion $\to$ Total Internal Reflection $\to$ Refraction out $\to$ Rainbow.
[Diagram: Rainbow formation in water droplet]
7. [Diagram: Refraction through glass prism showing $\angle i, \angle e, \angle D$]. $\angle i + \angle e = \angle A + \angle D$.
8. Due to atmospheric refraction, sun appears at horizon when it is actually below it. Light bends from vacuum to atmosphere.
[Diagram: Advance Sunrise due to refraction]
9. Myopia: Focal length decreased (Lens too curved). Hypermetropia: Focal length increased (Lens too flat).
[Diagram: Eye lens curvature comparison]
10. Light from stars bends towards normal as it travels down through denser and denser layers of atmosphere. Eye projects ray straight back to a higher position.
[Diagram: Shift in star position]
Module 2: Numerical Ability
11. Myopia (can't see far). Far point $x = 1.2$ m.
Using $f = -x$ for myopia correction: $f = -1.2$ m.
$P = 1/f = 1/(-1.2)$ $= -10/12 = -0.83$ D. Concave Lens.
12. Hypermetropia. Near point $N' = 1$ m = 100 cm. Normal near point $N = 25$ cm.
Object at $u = -25$ cm should form virtual image at $v = -100$ cm.
$1/f = 1/(-100) - 1/(-25)$ $= -1/100 + 4/100 = 3/100$.
$P = 100/f(\text{cm}) = 3$ D. Convex Lens.
13. $P = -2.5$ D. $f = 1/P = 1/(-2.5) = -0.4$ m = -40 cm.
Negative power indicates Concave lens, so defect is Myopia.
14. (i) Distant: $P=-5.5$D. $f = 1/(-5.5) = -0.18$ m (-18 cm).
(ii) Near: $P=+1.5$D. $f = 1/1.5 = +0.67$ m (+67 cm).
15. Far point = 80 cm (0.8 m).
$f = -0.8$ m. $P = 1/(-0.8) = -1.25$ D. Nature: Concave Lens.
16. Same question as Q12. $P = +3.0$ D.
17. Person wants to read at $u=-25$ cm, but can only focus at $v=-40$ cm.
$1/f = 1/(-40) - 1/(-25)$ $= -5/200 + 8/200$ $= 3/200$.
$f = 200/3$ cm = +66.67 cm. $P = 100/66.67 = +1.5$ D.
18. $n = c/v \implies v = c/n$.
$v = 3 \times 10^8 / 1.5 = 2 \times 10^8$ m/s.
19. Same as Q18. $v = 2 \times 10^8$ m/s.
20. Snell's Law: $n = \sin i / \sin r$.
$n = \sin 45^\circ / \sin 30^\circ$ $= (1/\sqrt{2}) / (1/2)$ $= 2/\sqrt{2} = \sqrt{2} = 1.414$.
21. ${}_w n_g = n_g / n_w = (3/2) / (4/3) = 9/8 = 1.125$.
22. Real, Inverted, Same Size means image is at $2F$. So $v = 2f = 50$ cm.
So $f = 25$ cm = 0.25 m. Object also at $2F = 50$ cm.
$P = 1/0.25 = +4.0$ D.
23. Critical angle $\sin C = 1/n = 1/1.5 = 0.666$.
Given $\sin 42^\circ \approx 0.67$. So $C \approx 42^\circ$.
24. $P = P_1 + P_2 = +3.5 - 2.5 = +1.0$ D.
$f = 1/P = 1$ m = 100 cm.
25. $h_o = 5, f = +20, u = -30$. Lens Formula: $1/v - 1/u = 1/f$.
$1/v = 1/20 + 1/(-30) = 3/60 - 2/60 = 1/60$. $v = +60$ cm (Real, behind lens).
$m = v/u = 60/(-30) = -2$. Image is Real, Inverted, Magnified ($10$ cm tall).
Module 3: Scientific Reasoning
26. In space, there is no atmosphere. No particles to scatter light. Scattering requires particles. Hence, no light enters eye from sky path $\to$ Dark.
27. At sunrise/set, light travels max distance through atmosphere. Blue/shorter wavelengths scatter away completely. Only Red (longest $\lambda$) remains to reach eye.
28. Stars are point sources; their light path changes due to atmospheric turbulence (refraction), causing fluctuating intensity (twinkle). Planets are extended disks; points average out.
29. Rayleigh Scattering. Air molecules scatter blue light ($I \propto 1/\lambda^4$) much more than red. This scattered blue light enters our eyes.
30. Red has longest wavelength. It is scattered the least by fog/smoke/air. So it is visible from the longest distance.
31. Planets are closer and appear as extended sources (collection of points). Variations in intensity from different points cancel each other out $\to$ No twinkling.
32. At noon, sun is overhead, light travels least distance. All colors scatter less, so they mix to appear white.
33. Near Point limit. Ciliary muscles cannot contract enough to make the lens curved/thick enough to focus objects closer than 25 cm (Max power reached).
34. Image distance remains constant ($v \approx 2.3$ cm, dist between lens and retina). Focal length changes to accommodate object distance.
35. (i) To increase horizontal field of view. (ii) For stereoscopic vision (depth perception/3D).
36. No. Apparent position is slightly higher than true position due to atmospheric refraction bending light towards the normal.
37. Rainbow requires water droplets in atmosphere to act as prisms (dispersion+TIR). Rainfall provides these droplets.
38. Red light scatters least and penetrates fog/mist best (Long wavelength).
39. Yes. Blue is scattered in all directions by observation path.
40. Clouds contain large water droplets (larger than $\lambda$ of light). Large particles scatter all wavelengths equally (Mie scattering) $\to$ White.
Module 4: Case-Based & Practical
41. Defect: Myopia (Near-sightedness). Cannot see distant objects (blackboard at 3m).
42. Correction: Concave Lens (Diverging Lens) of appropriate power.
43. [Diagram: Myopic correction with concave lens].
44. Bending: Violet bends most, Red bends least.
45. Cause: Different colors travel with different speeds in glass ($Speed \propto \text{Wavelength}$). Refractive index is different for each color.
46. Phenomenon: Rainbow.
47. Power is negative (-1.0 D), so lens is Concave. Defect is Myopia. He can see near objects clearly (so reading is fine), but distant objects are blurry without glasses.
48. Lens hardens with age (Presbyopia), loses accommodation. Can't focus near (needs Convex for reading). If also myopic for distance, needs Concave. Resolution: Bifocal Lenses (Upper: Concave, Lower: Convex).
49. Yellow light has longer wavelength than blue/violet, so it scatters less in fog, providing better contrast and visibility.
50. Fine smoke particles are small enough to cause Rayleigh scattering, scattering blue light more than red.