Watermark

VARDAAN LEARNING INSTITUTE

Level 3 Answer Key: Metals and Non-Metals

Class: 10 Science Type: HOTS & Case Studies Verified Answers
HOTS Questions
1. (a) Metal X = Iron (Fe). (b) X will displace Cu from CuSO$_4$ because Fe is more reactive than Cu.
$Fe(s) + CuSO_4(aq) \rightarrow FeSO_4(aq) + Cu(s)$
(c) X will NOT displace Zn from ZnSO$_4$ because Fe is less reactive than Zn.
2. Ionic Compounds have high melting points because they have strong electrostatic forces of attraction between oppositely charged ions. A lot of energy is needed to break these bonds.
3. Assertion (A): Gold is found in free state in nature. Reason (R): Gold is least reactive. Both A and R are True. R is the correct explanation of A.
4. Anodising: Process of forming a thick protective oxide layer on Aluminium by electrolysis. Al acts as the anode, and the natural oxide layer is made thicker, offering better corrosion resistance. The layer can be dyed for decoration.
5. Food cans are coated with Tin (not Zinc) because Tin is less reactive than Zinc and does not react with organic acids in food. Zinc would react and could be harmful.
Case Study: Thermite Reaction
6. Thermite Reaction:
$Fe_2O_3(s) + 2Al(s) \xrightarrow{\Delta} 2Fe(l) + Al_2O_3(s) + Heat$
7. This reaction is used for welding broken railway tracks or cracked machine parts.
8. It is a Displacement Reaction. Aluminium, being more reactive, displaces Iron from its oxide.
9. The reaction is highly exothermic. The heat generated is so intense (~2500°C) that Iron is produced in molten form.
Case Study: Electrolytic Refining
10. Impure metal is made the Anode. Pure metal strip is made the Cathode. Electrolyte is a solution of the metal salt (e.g., CuSO$_4$ for Copper).
11. At Anode: Impure metal dissolves as ions ($Cu \rightarrow Cu^{2+} + 2e^-$). At Cathode: Pure metal is deposited ($Cu^{2+} + 2e^- \rightarrow Cu$).
12. Insoluble impurities (like gold, silver) settle at the bottom of the anode as Anode Mud, which is collected.
Miscellaneous
13. Carbonate and Sulphide ores cannot be reduced directly with Carbon because they are not stable under high temperatures. They first need to be converted to oxides by Roasting (Sulphide) or Calcination (Carbonate).
14. When a metal reacts with a base, it releases Hydrogen gas (if it is Amphoteric, like Zinc or Aluminium).
$Zn(s) + 2NaOH(aq) \rightarrow Na_2ZnO_2(aq) + H_2(g)$