Q1. Area = $\frac{\theta}{360} \pi r^2 = \frac{60}{360} \times \frac{22}{7} \times 6^2 = \frac{132}{7} = 18.86\text{ cm}^2$.
Q2. A round table cover has six equal designs. If the radius of the cover is 28 cm, find the cost of making the designs at the rate of $ .35 per $\text{cm}^2$ (Use $\sqrt{3} = 1.7$).
Q3. RP is diameter (angle in semicircle is $90^\circ). $RQ^2 = PR^2 + PQ^2 = 7^2 + 24^2 = 625 \rightarrow RQ = 25\text{ cm}. Shaded Area = Area of Semicircle - Area of Triangle = $161.31\text{ cm}^2$.
Q4. A chord of a circle of radius 15 cm subtends an angle of $60^\circ$ at the centre. Find the areas of the corresponding minor and major segments of the circle.
Q5. Distance in 10 mins = 11 km. Circumference = $80\pi\text{ cm}. Number of revolutions = $\frac{1100000}{80\pi} = 4375$.
