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Sound Waves: Characteristics And Applications

Class 9 Science - Detailed NCERT Notes

1. Production of Sound

Sound is a form of energy which produces a sensation of hearing in our ears. Just like light and heat, sound is an energy form, but unlike them, it requires physical movement or vibration of particles to be produced.

Tuning Fork Vibrations

Activity 10.2 (NCERT): Striking a tuning fork prong against a soft rubber pad makes it vibrate and emit a sound. If a vibrating prong touches the surface of water in a glass, ripples and splashes are immediately produced, visually proving that the prongs are vibrating rapidly to generate sound.

NCERT Figure 10.3: Anatomy of Human Vocal Cords & Larynx
Figure 10.3: Vocal cords in humans (Open during breathing vs Closed/vibrating during sound creation)
NCERT Curiosity Note: Kongthong Whistling Village

In Kongthong village near Shillong (Meghalaya), known as the Whistling Village, every person has a unique tune name composed by their mother at birth. This tradition is called Jingrwai Iawbei, where people call out to each other across hills using musical whistling tones.

2. Propagation of Sound & Requirement of a Medium

The matter or substance through which sound is transmitted is called a medium. It can be a solid, liquid, or gas.

2.1 Mechanism of Propagation (Compressions and Rarefactions)

When an object vibrates, it displaces adjacent particles of the medium. Important: The particles themselves do not travel all the way from the source to the ear. Each particle vibrates back and forth around its mean position, transferring energy to neighbouring particles. It is the disturbance (wave) that propagates through the medium.

As the source vibrates continuously back and forth, a series of alternating compressions and rarefactions moves outward through the medium, forming a sound wave.

2.2 Sound Needs a Material Medium to Travel (Cannot Travel in Vacuum)

Sound is a mechanical wave and requires a material medium (air, water, steel) for propagation. In outer space (a vacuum), sound waves cannot propagate. Astronauts on spacewalks rely on radio signals inside their helmets to communicate.

NCERT Figure 10.7 & 10.9: Vacuum Bell Jar Experiment and Air Density Propagation Model
Figures 10.7 & 10.9: Vacuum Bell Jar Experiment (left) and Piston Air Density Model producing Compressions (C) & Rarefactions (R) (right)

3. Types of Waves: Longitudinal Waves vs Transverse Waves

Waves are classified based on the relative direction of particle displacement with respect to the wave's propagation direction:

Parameter Longitudinal Waves (e.g., Sound in Air) Transverse Waves (e.g., Light, String Waves)
Particle Oscillation Particles oscillate parallel ($\leftrightarrow$) to the direction of wave propagation. Particles oscillate perpendicular ($\updownarrow$) to the direction of wave propagation.
Structure Consists of alternating Compressions (C) and Rarefactions (R). Consists of alternating Crests (peaks) and Troughs (valleys).
Medium Requirement Mechanical wave; strictly requires a physical medium. Can be mechanical (water/string waves) or non-mechanical (light/electromagnetic waves).
NCERT Figure 10.12 & 10.13: Longitudinal Wave vs Transverse Wave Motion
Figures 10.12 & 10.13: Particle oscillation in Longitudinal Waves (parallel) vs Transverse Waves (perpendicular)
Seismic Waves in Earthquakes

Earthquakes generate both longitudinal and transverse seismic waves through the Earth. Seismographs detect primary longitudinal waves (P-waves) first because they travel faster through terrestrial rock layers than secondary transverse waves (S-waves).

4. Energy of Sound Waves & Energy Conversion

Sound carries energy transferred from the vibrating source. In Activity 10.6 (NCERT), when grains of salt or semolina are sprinkled over a stretched rubber membrane on a bowl and a loud sound is produced nearby, the grains dance up and down. This demonstrates that sound waves transfer kinetic energy through medium particles.

Transducers: Microphones & Speakers

5. Graphical Representation of a Sound Wave

As a sound wave propagates, the density (or pressure) of the medium varies periodically with distance from the source. A sine wave graph models these density variations:

NCERT Figure 10.16: Master Graphical Representation of a Sound Wave
Figure 10.16: Alignment of medium particle density variations (a) with the corresponding Density vs Distance Sine Wave Graph (b)

6. Characteristics of a Sound Wave

Every sound wave is defined by five key physical characteristics:

6.1 Wavelength ($\lambda$)

The distance between two consecutive compressions (C) or two consecutive rarefactions (R) (or two consecutive crests / troughs) is called the wavelength.

NCERT Figure 10.18: Long Wavelength vs Short Wavelength Comparison
Figure 10.18: Graphical comparison of (a) Long Wavelength (Low Frequency) vs (b) Short Wavelength (High Frequency)

6.2 Frequency ($\nu$)

The number of complete density oscillations (C-R-C cycles) per unit time at a fixed location in the medium is called the frequency.

6.3 Time Period ($T$)

The time required for one complete oscillation in density/pressure at a fixed point (or the time taken for two consecutive compressions to pass a fixed point) is called the time period.

$$ \nu = \frac{1}{T} \quad \text{or} \quad T = \frac{1}{\nu} $$

6.4 Amplitude ($A$)

The magnitude of the maximum disturbance or maximum change in density/pressure from its mean value is called the amplitude.

NCERT Figure 10.20: Low Amplitude vs High Amplitude Comparison
Figure 10.20: Comparison of (a) Low Amplitude (Soft Sound) vs (b) High Amplitude (Loud Sound)

6.5 Speed of Sound ($v$)

The speed of sound is the distance traveled by a wave point (like a crest or compression) per unit time.

$$ v = \frac{\text{Distance}}{\text{Time}} = \frac{\lambda}{T} = \lambda \times \nu $$

Speed = Wavelength × Frequency ($v = \lambda \nu$)

6.6 Intensity vs. Loudness

Parameter Intensity of Sound Loudness of Sound
Definition Amount of sound energy passing through unit area perpendicular to propagation per unit time. Subjective auditory perception of the ear to the sound wave.
Nature Objective, measurable physical quantity ($I \propto A^2$). Subjective; depends on both energy amplitude and ear sensitivity.
Unit $\text{Watts per square metre (W/m}^2\text{)}$. Decibels (dB).
Distance Variation Decreases with distance ($I \propto 1/r^2$) as wave energy spreads over a larger spherical surface ($4\pi r^2$). Decreases as listener moves farther from the source.

7. Pitch, Loudness, and Quality (Timbre)

NCERT Figure 10.25: Pure Tone vs Musical Note Waveforms
Figure 10.25: Waveforms of (a) Single-frequency Tone (Tuning fork/whistle) vs (b) Multi-frequency Musical Note (Singing voice/tanpura)
Property Determined By Description & NCERT Examples
Pitch Frequency ($\nu$) Higher frequency = higher pitch (shrill voice, e.g., bird chirping, whistling, woman's voice). Lower frequency = lower pitch (deep voice, e.g., lion's roar, drum beat, man's voice).
Loudness Amplitude ($A$) Striking a surface harder imparts more kinetic energy $\to$ higher amplitude $\to$ louder sound. Decibel scale (dB): Rustling leaves $\approx 10\text{ dB}$, Normal talk $\approx 60\text{ dB}$, Loud noise $> 100\text{ dB}$.
Timbre / Quality Waveform Shape (Overtones) Enables us to distinguish two instruments (e.g., flute vs. sitar) playing the same pitch and loudness. A pure single frequency is a Tone; a pleasant mix of fundamental and overtone frequencies is a Note. An Octave is a frequency doubling interval ($200\text{ Hz} \to 400\text{ Hz}$).
Scientist Focus: Sir C. V. Raman

Sir C. V. Raman (Nobel Prize in Physics) conducted pioneering research on acoustics of Indian percussion instruments like the tabla and mridangam. He analyzed how the central black patch (syaahi) on the drum membrane alters acoustic modes to produce rich harmonic overtones.

8. Speed of Sound in Different Media

The speed of sound depends on the state of matter, elasticity, density, temperature, and humidity of the medium.

Sonic Boom

When an object (fighter jet, bullet) moves faster than the speed of sound in air, it travels at supersonic speed. This source moves faster than its generated sound waves, creating high-energy conical shock waves. The abrupt air pressure jump associated with shock waves produces a sudden, intense explosion sound called a sonic boom, capable of breaking window panes and structural glass.

9. Reflection of Sound

Sound bounces off solid or liquid obstacles obeying the standard Laws of Reflection:

  1. The angle of incidence equals the angle of reflection ($\angle i = \angle r$).
  2. The incident wave, reflected wave, and normal at the point of incidence all lie in the same plane.

9.1 Echo

An echo is the repetition of sound caused by reflection off a distant hard obstacle (cliff, wall, tall building).

9.2 Reverberation

In large halls or auditoriums, sound undergoes multiple successive reflections from walls, ceiling, and floor. The persistence of sound due to repeated reflections arriving with time gaps $< 0.05\text{ s}$ is called reverberation.

Acoustic Architecture: Gol Gumbaz Whispering Gallery

The Whispering Gallery in the dome of Gol Gumbaz (Bijapur, Karnataka) is designed such that a soft whisper at one side reflects multiple times around the circular dome, enabling a person on the opposite side to hear it clearly.

9.3 Applications of Multiple Reflection of Sound

  1. Megaphones & Horns: Conical tubes guide sound waves forward by successive reflections, preventing radial spreading.
  2. Stethoscope: Medical tool where heart/lung sounds travel to doctor's earpieces via multiple internal reflections inside the flexible tubing.
  3. Curved Auditorium Ceilings & Soundboards: Curved ceilings and soundboards behind stage reflect sound uniformly to all seating corners.

10. Range of Hearing & Infrasonic / Ultrasonic Waves

10.1 Key Applications of Ultrasound

  1. Industrial Cleaning: High-frequency ultrasound in cleaning baths detaches grease, dirt, and dust from hard-to-reach parts (spiral tubes, electronic components).
  2. Metal Flaw/Crack Detection: Ultrasonic waves sent through structural metal blocks pass through intact metal, but reflect back at internal cracks/voids to alert flaw detectors.
  3. Echocardiography: Ultrasonic reflections map heart wall motion and internal valve functions.
  4. Medical Ultrasonography: Scanners use ultrasound to image internal organs (liver, kidneys, uterus, gallbladder) and monitor fetal growth.
  5. Lithotripsy: High-intensity ultrasonic pulses break kidney stones into microscopic grains flushed out through urine.

11. Echolocation & SONAR

NCERT Figure 10.27 & 10.28: Echolocation in Bats and Working of SONAR
Figures 10.27 & 10.28: Echolocation in bats using ultrasonic echoes (left) and SONAR echo-ranging system in ships (right)

SONAR (Sound Navigation And Ranging): Method using ultrasound to calculate depth, distance, speed, and location of underwater objects (submarines, icebergs, sunken ships).

$$ 2d = v \times t \quad \implies \quad d = \frac{v \times t}{2} $$

where $d$ is depth/distance, $v$ is sound speed in seawater ($\approx 1530\text{ m/s}$), and $t$ is total echo round-trip time.

12. Structure of the Human Ear

The human ear converts air pressure variations into electrical nerve impulses sent to the brain:

  1. Outer Ear: Consists of the Pinna (collects sound waves), Auditory Canal, and the Tympanic Membrane (Eardrum). Compressions push the eardrum inward; rarefactions pull it outward, making it vibrate.
  2. Middle Ear: Contains three tiny lever bones—the Hammer (Malleus), Anvil (Incus), and Stirrup (Stapes)—which amplify eardrum vibrations several times.
  3. Inner Ear: Amplified vibrations enter the liquid-filled Cochlea, which converts pressure signals into electrical impulses transmitted via the Auditory Nerve to the brain.
NCERT Figure 10.24: Schematic Anatomy of Human Ear
Figure 10.24: Schematic diagram of human ear anatomy showing Eardrum, Middle Ear bones, Cochlea, and Auditory Nerve

13. Summary Formula Sheet & NCERT Solved Examples

Master Formula Reference

NCERT Solved Numerical Examples

NCERT Example 10.1: If there are 10 density oscillations in 2 seconds at a given position, calculate (i) frequency, and (ii) time period of the sound wave.

Solution:

(i) Frequency $\nu = \frac{\text{Number of oscillations}}{\text{Time taken}} = \frac{10}{2\text{ s}} = \mathbf{5\text{ Hz}}$.

(ii) Time Period $T = \frac{1}{\nu} = \frac{1}{5\text{ Hz}} = \mathbf{0.2\text{ s}}$.

NCERT Example 10.2: Human hearing roughly spans $20\text{ Hz}$ to $20\text{ kHz}$. What are the corresponding wavelengths in air? (Use speed of sound in air $v = 344\text{ m/s}$).

Solution: Using $\lambda = \frac{v}{\nu}$:

(i) For $\nu_1 = 20\text{ Hz}$: $\lambda_1 = \frac{344\text{ m/s}}{20\text{ s}^{-1}} = \mathbf{17.2\text{ m}}$.

(ii) For $\nu_2 = 20,000\text{ Hz}$: $\lambda_2 = \frac{344\text{ m/s}}{20,000\text{ s}^{-1}} = 0.0172\text{ m} = \mathbf{1.72\text{ cm}}$.

NCERT Example 10.3: During a thunderstorm, lightning is seen before thunder is heard. If the time delay between seeing lightning and hearing thunder is $5\text{ s}$, estimate the distance to the lightning strike. (Speed of sound in air $v = 340\text{ m/s}$).

Solution: Distance $d = v \times t = 340\text{ m/s} \times 5\text{ s} = 1700\text{ m} = \mathbf{1.7\text{ km}}$.

NCERT Example 10.4: A sound wave propagating in steel has a wavelength $\lambda = 50\text{ m}$ and speed $v = 5000\text{ m/s}$. Find its frequency and time period.

Solution:

Frequency $\nu = \frac{v}{\lambda} = \frac{5000\text{ m/s}}{50\text{ m}} = \mathbf{100\text{ Hz}}$.

Time Period $T = \frac{1}{\nu} = \frac{1}{100\text{ Hz}} = \mathbf{0.01\text{ s}}$.

NCERT Example 10.5: You clap in an empty corridor and hear an echo after $0.5\text{ s}$. If sound speed in air is $340\text{ m/s}$, calculate your distance from the wall.

Solution: Distance $d = \frac{v \times t}{2} = \frac{340\text{ m/s} \times 0.5\text{ s}}{2} = \mathbf{85\text{ m}}$.

NCERT Example 10.6: A naval SONAR signal sent into seawater returns after $0.90\text{ s}$. The speed of sound in seawater is $1530\text{ m/s}$. How far is the underwater object?

Solution: Distance $d = \frac{v \times t}{2} = \frac{1530\text{ m/s} \times 0.90\text{ s}}{2} = 1530 \times 0.45 = \mathbf{688.5\text{ m}}$.