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Alcohols (Alkanols)

CBSE Class 12 & JEE Mains • Module 11 of 20 • The Hydroxyl Group — From Fermentation to Synthesis

📍 Chapter Overview

Alcohols — Complete Mind Map

Topics Covered: Classification (Mono/Di/Trihydric, Allylic, Vinylic) · Preparation (Acid-catalyzed Hydration, Hydroboration-Oxidation, Grignard additions) · Physical Properties (BP elevation due to H-bonds) · Chemical Reactions (Acidity scale, Esterification, Dehydration to Alkenes/Ethers, PCC Oxidation) · Distinction Tests (Lucas Test)

🤖 AI Prompt — Chapter Mind Map: Emerald-green themed mind map on dark background. Central node: "ALCOHOLS — R-OH" in bright white. Six branches: (1) "Classification" — 1° (R-CH2OH), 2° (R2-CH-OH), 3° (R3-C-OH), Allylic (CH2=CH-CH2OH), Vinylic (CH2=CH-OH); (2) "Preparation from Alkenes" — Acid hydration (Markovnikov) and Hydroboration (anti-Markovnikov); (3) "Grignard Route" — arrows showing 1°/2°/3° alcohol formation from HCHO, RCHO, R2CO; (4) "Physical Prop" — intermolecular hydrogen bonding between R-O-H molecules shown as dashed lines; (5) "Chemical Reactions" — Dehydration (Alkene at 443K), Oxidation (Aldehyde with PCC, Ketone with Cu/573K); (6) "Industrial" — Methanol (Wood spirit) and Ethanol (Fermentation). High resolution educational infographic.

1. Classification and Nomenclature

Primary (1°) Alcohol: -OH group attached to carbon bonded to 1 other carbon. e.g. Ethan-1-ol ($CH_3CH_2OH$).

Secondary (2°) Alcohol: -OH attached to carbon bonded to 2 other carbons. e.g. Propan-2-ol ($CH_3CH(OH)CH_3$).

Tertiary (3°) Alcohol: -OH attached to carbon bonded to 3 other carbons. e.g. 2-Methylpropan-2-ol ($(CH_3)_3COH$).

Allylic Alcohol: -OH on $sp^3$ C adjacent to $C=C$. e.g. Prop-2-en-1-ol ($CH_2=CH-CH_2OH$).

Vinylic Alcohol: -OH directly on $C=C$. e.g. Ethenol ($CH_2=CHOH$) — unstable, tautomerizes to ethanal.

2. Preparation of Alcohols

2.1 Acid Catalyzed Hydration of Alkenes

Reaction: $Alkene + H_2O \xrightarrow{H^+} Alcohol$ (Follows **Markovnikov’s Rule**) — *NCERT Section 7.4.1*

Mechanism: Acid Catalyzed Hydration (NCERT Page 199, Section 7.4.1)
Draw a 3-step mechanism for the acid-catalyzed hydration of ethene on white background. Step 1: "Protonation". Ethene ($CH_2=CH_2$) near $H_3O^+$. Curved arrow from the double bond to one H of $H_3O^+$. Arrow from $O—H$ bond to O. Product: Ethyl carbocation ($CH_3—CH_2^+$) + $H_2O$. Step 2: "Nucleophilic attack". Arrow from lone pair of $H_2O$ oxygen to the positively charged carbocation. Product: Protonated alcohol ($CH_3—CH_2—O^+(H)—H$). Step 3: "Deprotonation". Another $H_2O$ molecule nearby. Arrow from O lone pair of water to the extra H of the protonated alcohol. Arrow from $O—H$ bond back to the Oxygen atom. Final Product: Ethanol ($CH_3CH_2OH$) + $H_3O^+$. Clear bold structural formulas, arrows highlighting electron movement as per NCERT style. Label all steps as (i), (ii), (iii).

2.2 Hydroboration-Oxidation

Alkenes + Diborane ($B_2H_6$) followed by $H_2O_2/OH^-$: Result is **Anti-Markovnikov** addition of water. — *NCERT Section 7.4.1 (1)(ii)*

$3 CH_3—CH=CH_2 \xrightarrow{(i) BH_3, (ii) H_2O_2/OH^-} 3 CH_3—CH_2—CH_2OH$ (Propan-1-ol)

2.3 From Carbonyl Compounds (Grignard Reagents)

Reaction Name: Grignard addition to Carbonyls (NCERT Page 200, Section 7.4.1)

Mechanism: Grignard Attack on Carbonyl (NCERT Page 200)
Draw the mechanism of nucleophilic addition of Grignard reagent to a general carbonyl ($>C=O$) on white background. Step 1: Show the carbonyl group $>C=O$ and Grignard $R—MgX$. Curved arrow from the $R—Mg$ bond (nucleophilic R) to the Carbonyl Carbon. Curved arrow from one of the $C=O$ double bonds to the Oxygen atom. Product: Adduct (magnesium alkoxide) shown as $>C(R)—O^—Mg^+X$. Step 2: Addition of water ($H_2O$). Arrow from $O^-$ to H of water. Product: Alcohol and basic magnesium halide ($Mg(OH)X$). Clear skeletal structures, arrows showing electron shifts. Label: "Grignard Addition to Carbonyl Group".

3. Physical Properties

Boiling Points: Alcohols have higher BP than hydrocarbons/ethers of similar mass due to **Intermolecular Hydrogen Bonding**. — *NCERT Section 7.4.3*

Solubility: Solubility in water decreases as the size of the alkyl group ($Hydrophobic$) increases. Ethanol is highly soluble, but Butanol is less soluble.

4. Chemical Reactions

4.1 Acidity of Alcohols

Acidity scale: $1^\circ > 2^\circ > 3^\circ$ — *NCERT Section 7.5.1*

Why? Electron donating alkyl groups ($+I$ effect) increase electron density on Oxygen, making the $O—H$ bond less polar and destabilizing the alkoxide ion ($R—O^-$).

4.2 Dehydration to Alkenes

Ethanol $\xrightarrow{H_2SO_4, 443K}$ Ethene + $H_2O$ — *NCERT Page 207, Section 7.5.2 (3)*

Mechanism: Dehydration of Ethanol (NCERT Page 207, Section 7.5.2)
Draw a 3-step mechanism for ethanol dehydration on white background. Step 1 (Protonation): Ethanol + $H^+$. Arrow from O lone pair to $H^+$. Product: Protonated alcohol. Step 2 (Carbocation formation): Arrow from the $C—O$ bond to the $O^+$ of the leaving water molecule. This is the SLOW STEP (RDS). Product: Ethyl carbocation ($CH_3CH_2^+$) + $H_2O$. Step 3 (Elimination): Arrow from one $C—H$ bond electrons to the $C—C$ bond to form a double bond, while $H^+$ leaves. Product: Ethene ($CH_2=CH_2$). Clear labeling of (i), (ii), (iii) and RDS step. NCERT style.

4.3 Oxidation of Alcohols

NCERT Page 208, Section 7.5.2 (4)

5. Distinction Test: Lucas Test

Reagent: Conc. $HCl$ + anhydrous $ZnCl_2$ (Lucas Reagent)

Practice Problems

E Q1. Arrange the following in increasing order of boiling point: Propan-1-ol, Butan-1-ol, Butan-2-ol, Pentan-1-ol. *(NCERT Reference)*

M Q2. Write the mechanism of the reaction of HI with methoxyethane. *(Refer to Module 13 for details, but relevant here)*

M Q3. Explain why $3^\circ$ alcohols give an alkene instead of a ketone when passed over hot copper at 573K.

H Q4. You are given two bottles containing Pentan-2-ol and Pentan-3-ol. Can Lucas test distinguish them? If not, suggest another chemical test.

  1. Saying $NaBH_4$ can reduce carboxylic acids — WRONG! $NaBH_4$ is too weak; it only reduces aldehydes and ketones. $LiAlH_4$ is needed for acids.
  2. Writing the Grignard adduct with $H$ instead of $MgX$ — Correct first step adduct is an alkoxide magnesium halide ($OMgX$).
  3. Confusing the temperature for ether formation vs alkene formation: **413K** for Ether, **443K** for Alkene.
ReactantConditionProduct
AlkeneAcid Hydration ($H^+$)Alcohol (Markovnikov)
AlkeneHydroboration-OxidationAlcohol (Anti-Markovnikov)
Aldehyde/KetoneGrignard ($RMgX$)1°/2°/3° Alcohols
Alcohol$H_2SO_4, 443K$Alkene
Alcohol (1°)$PCC$Aldehyde
Alcohol (1°)$K_2Cr_2O_7$Carboxylic Acid